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Find the p H of a 0.150M solution of a weak monoprotic acid having K a= 2.010 ?5

ID: 874280 • Letter: F

Question

Find the pH of a 0.150M solution of a weak monoprotic acid having Ka= 2.010?5.

Express your answer to two decimal places.

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Correct

Significant Figures Feedback: Your answer 2.79 was either rounded differently or used a different number of significant figures than required for this part.

Part B

Find the percent dissociation of this solution.

Express your answer using two significant figures.

Part C

Find the pH of a 0.150M solution of a weak monoprotic acid having Ka= 2.010?3.

Express your answer to two decimal places.

Part D

Find the percent dissociation of this solution.

Express your answer using two significant figures.

Part E

Find the pH of a 0.150M solution of a weak monoprotic acid having Ka= 0.10.

Express your answer to two decimal places.

Part F

Find the percent dissociation of this solution.

Express your answer using two significant figures.

pH = 2.76

Explanation / Answer

a)Find the pH of a 0.150M solution of a weak monoprotic acid having Ka= 2.0*10-5.

given value pH =2.76; correct

b)

find % dissocaition = [H+]/M *100% = (10^-2.76) / (0.150) * 100% = 1.16 %

c)

Find the pH of a 0.150M solution of a weak monoprotic acid having Ka= 2.010?3.

Ka = [H+][A-]/[HA]

2*10^-3 = (x*x)/(0.15-x)

x = H = 0.01634

pH = -log(H) = -log(0.01634) = 1.79

d)

find % dissocaition = [H+]/M *100% = 0.01634 / (0.150) * 100% = 10.89 %

e)

Find the pH of a 0.150M solution of a weak monoprotic acid having Ka= 0.10.

Ka = [H+][A-]/[HA]

0.1 = x*x/(0.15-x)

x = [H+] = 0.08228

pH = -log(0.08228) = 1.08

f)

find % dissocaition = [H+]/M *100% = 0.08228/ (0.150) * 100% = 54.85%

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