Find the p H of a 0.150M solution of a weak monoprotic acid having K a= 2.010 ?5
ID: 874280 • Letter: F
Question
Find the pH of a 0.150M solution of a weak monoprotic acid having Ka= 2.010?5.
Express your answer to two decimal places.
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Significant Figures Feedback: Your answer 2.79 was either rounded differently or used a different number of significant figures than required for this part.
Part B
Find the percent dissociation of this solution.
Express your answer using two significant figures.
Part C
Find the pH of a 0.150M solution of a weak monoprotic acid having Ka= 2.010?3.
Express your answer to two decimal places.
Part D
Find the percent dissociation of this solution.
Express your answer using two significant figures.
Part E
Find the pH of a 0.150M solution of a weak monoprotic acid having Ka= 0.10.
Express your answer to two decimal places.
Part F
Find the percent dissociation of this solution.
Express your answer using two significant figures.
pH = 2.76Explanation / Answer
a)Find the pH of a 0.150M solution of a weak monoprotic acid having Ka= 2.0*10-5.
given value pH =2.76; correct
b)
find % dissocaition = [H+]/M *100% = (10^-2.76) / (0.150) * 100% = 1.16 %
c)
Find the pH of a 0.150M solution of a weak monoprotic acid having Ka= 2.010?3.
Ka = [H+][A-]/[HA]
2*10^-3 = (x*x)/(0.15-x)
x = H = 0.01634
pH = -log(H) = -log(0.01634) = 1.79
d)
find % dissocaition = [H+]/M *100% = 0.01634 / (0.150) * 100% = 10.89 %
e)
Find the pH of a 0.150M solution of a weak monoprotic acid having Ka= 0.10.
Ka = [H+][A-]/[HA]
0.1 = x*x/(0.15-x)
x = [H+] = 0.08228
pH = -log(0.08228) = 1.08
f)
find % dissocaition = [H+]/M *100% = 0.08228/ (0.150) * 100% = 54.85%
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