When 0.075 g of the antibiotic, pehicillamine is dissolved in 10.0 mL of pyridin

Question

When 0.075 g of the antibiotic, pehicillamine is dissolved in 10.0 mL of pyridine and placed in a sample cell of 100.0 mm in length, the observed rotation at 20degree C. using the D-sodium line is -0.47 degree. What will be the specific rotation of this sample of penicillamine? 11. The activation barrier that passes the highest energy point on a potential energy diagram: a. determines if a reaction will be exothermic b. determines if a reaction will be endothermic c. indicates the number of intermediates that will be present in a reaction d. affects the overall rate of the reaction e. must be the first step of every reaction (11 Draw all the stereo isomeric structures of 3, 4-dimethylhexane and assign R or S configurations to all the chiral centers in all your stereoisomers.

Explanation / Answer

Solution :- for first question

Given data

Mass = 0.075 g

Volume = 10.0 ml

Length = 100 mm

Observed rotation ? = -0.47 degree

Formula to calculate specific rotation is as follows

[?]1 = ? / l*c

Where, [?] = Specific rotation, ?= observed rotation , l= length in dm , c = concentration in g/ml

Lets convert length from mm to dm

(100 mm * 1 dm) / 100 mm = 1 dm

Calculate concentration in g/ml

c = 0.075 g / 10.0 ml = 0.0075 g/ml

now lets put the values in the formula and calculate specific rotation

[?]1 = ? / l*c

[?]1= -0.47o / ( 1 dm * 0.0075 g/ml)

[?]1 = -62.7o

Specific rotation = -62.7 degrees

Solution for Q 11

Answer is option e that is

e) must be the first step of every reaction

Following are the stereoisomeric structures of the 3,4-dimethylhexane with

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