In the following reaction 2 Co(CO)5 ? Co2(CO)10 A plot of 1/[Co(CO)5] vs. time (

Question

In the following reaction

2 Co(CO)5 ? Co2(CO)10

A plot of 1/[Co(CO)5] vs. time (seconds) is linear and the slope is equal to 0.25. If initially 0.25 moles of Co(CO)5 is present in 0.5 L of the solution, how long will it take for it to reduce to 0.10 moles.

In the following reaction

2 Co(CO)5 ? Co2(CO)10

A plot of 1/[Co(CO)5] vs. time (seconds) is linear and the slope is equal to 0.25. If initially 0.25 moles of Co(CO)5 is present in 0.5 L of the solution, how long will it take for it to reduce to 0.10 moles.

Explanation / Answer

As a plot of Co(CO)5 1/[Co(CO)5] vs. time (seconds) is linear and the slope is equal to 0.25

so reaction is of second order reaction with k = slope of the line = 0.25

Initial concentration = 0.25 / 0.5 = 0.5 Mole / L

second order equation is

1/[A] =1/[A] 0  + kt

final conc = 0.1 / 0.5 = 0.2

1/0.2= 1/0.5 + 0.25 X t

5 = 2 + 0.25 t

3/0.25 =time = 12 seconds

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