In the following reaction 10.2 g of aniline and 12.96 g of acetic anhydride are

Question

In the following reaction 10.2 g of aniline and 12.96 g of acetic anhydride are reacted with 16.0031 g of sodium acetate trihydrate to make acetanilide. The product was purified and acetanilide was extracted. The actual mass of acetanilide was 2.1234g. Determine the theoretical yield and the percent yield. In the following reaction 10.2 g of aniline and 12.96 g of acetic anhydride are reacted with 16.0031 g of sodium acetate trihydrate to make acetanilide. The product was purified and acetanilide was extracted. The actual mass of acetanilide was 2.1234g. Determine the theoretical yield and the percent yield.

Explanation / Answer

1 mole of aniline requires 1 mole of acetic anhydride.

molar masses : Aniline =93 and acetic anhydride = 102, moles : Aniline = 10.2/93=0.1096 acetic anhydride = 12.96/102 = 0.1271, actual molar ratio = 0.1096 : 0.1271 excess is acetic anhydride and limiting is aniline. Moles of acetanilide formed = 0.1096, molar mass of aniline = 135 mass of acetanilide formed = 135*0.1096=14.8 gm

this is the theoretical yield, Actual yield d = 2,1234 gm. % yield = 100*2.1234/14.8 =14.34%

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