Consider the following balanced equation: SiO2( s )+3C( s )SiC( s )+2CO( g ) Com

Question

Consider the following balanced equation: SiO2(s)+3C(s)SiC(s)+2CO(g) Complete the following table showing the appropriate number of moles of reactants and products. If the number of moles of a reactant is provided, fill in the required amount of the other reactant, as well as the moles of each product formed. If the number of moles of a product is provided, fill in the required amount of each reactant to make that amount of product, as well as the amount of the other product that is made

Mol SiO2 Mol C Mol SiC Mol CO 1 _____ _____ _____ _____ 6 _____ _____ _____ _____ _____ 14 1.8 _____ _____ _____ _____ 1.85 _____ _____

Explanation / Answer

Answer –

We are given balanced reaction –

SiO2(s)+3C(s) -----> SiC(s)+2CO(g)

We need to calculate moles of reactant or product when we are given moles of 1 reactant or product.

From the balanced equation we know,

1 moles of SiO2 reacted with 3 moles of C and there are formed 1 moles of SiC and 2 moles of CO mean,

1 moles of SiO2 = 3 moles of C = 1 moles of SiC = 2 moles of CO

First row-

We are given moles of SiO2 = 1 moles

So we know when 1 mole of SiO2 reacted it required 3 moles of C and there are formed 1 moles of SiC and 2 moles of CO

So first row is 1 ,3 , 1, 2

Second row –

We are given 6 moles of C

So first we need to calculate moles of SiO2

We know,

3 moles of C = 1 moles of SiO2

So, 6 moles of C = ?

= 6 moles of C * 1 moles of SiO2 / 3 moles of C

= 2 moles of SiO2

Moles of SiC also same with SiO2, because mole ratio between SiO2 and SiC is same 1:1

So moles of SiC = 2 moles

Moles of CO

We know,

3 moles of C =2 moles of CO

So, 6 moles of C = ?

= 6 moles of C * 2 moles of CO / 3 moles of C

= 4 moles of CO

So second row is – 2 , 6, 2 , 4

Third row –

We are given, moles of CO = 14

We know,

2 moles of CO = 1 moles of SiO2

So, 14 moles of CO = ?

= 7 moles of SiO2

Moles of C

2 moles of CO = 3 moles of C

So 14 moles of CO = ?

= 21 moles of C

Moles of SiC = moles of SiO2

So moles of SiC = 7 moles

So, third row is 7, 21 , 7 , 14

Fourth row –

Given , 1.8 moles of SiO2

So we know, moles of SiO2 = moles of SiC

So, moles of SiC = 1.8 mole

Moles of C

1 moles of SiO2 = 3 moles of C

So, 1.8 moles of SiO2 = ?

= 5.4 moles of C

Moles of CO

1 moles of SiO2 = 2 moles of CO

So, 1.8 moles of SiO2 = ?

= 3.6 moles of CO

So fourth row is – 1.8 , 5.4 , 1.8 , 3.6

Fifth row –

We are given 1.85 moles of C

So first we need to calculate moles of SiO2

We know,

3 moles of C = 1 moles of SiO2

So, 1.85 moles of C = ?

= 1.85 moles of C * 1 moles of SiO2 / 3 moles of C

= 0.62 moles of SiO2

Moles of SiC also same with SiO2, because mole ratio between SiO2 and SiC is same 1:1

So moles of SiC = 0.62 moles

Moles of CO

We know,

3 moles of C =2 moles of CO

So, 1.85 moles of C = ?

= 1.85 moles of C * 2 moles of CO / 3 moles of C

= 1.23 moles of CO

So fifth row row is – 0.62 , 1.85 , 0.62 , 1.23

Final answered table is -

Mol SiO2

Mol C

Mol SiC

Mol CO

1

3

1

2

2

6

2

4

7

21

7

14

1.8

5.4

1.8

3.6

0.62

1.85

0.62

1.23

Mol SiO2

Mol C

Mol SiC

Mol CO

1

3

1

2

2

6

2

4

7

21

7

14

1.8

5.4

1.8

3.6

0.62

1.85

0.62

1.23

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