Chem 19.8 Part A: Chem 19.8 Part A: How many grams of nickel metal will be depos

Question

Chem 19.8

Part A:

Chem 19.8 Part A: How many grams of nickel metal will be deposited from a solution that contains Ni2+ ions if a current of 0.824 A is applied for 52.7 minutes grams Part B: How many grams of lead metal will be deposited from a solution that contains Pb+ ions if a current of 0.790 A is applied for 34.7 minutes. grams Chem 19.8 Part A: How many grams of nickel metal will be deposited from a solution that contains Ni2+ ions if a current of 0.824 A is applied for 52.7 minutes grams Part B: How many grams of lead metal will be deposited from a solution that contains Pb+ ions if a current of 0.790 A is applied for 34.7 minutes. grams

Explanation / Answer

W = Z * C * t

W = mass of the substance

Z = Electrochemical equivalent

C = current in amperes

t = time in seconds

Z = equivalent weight / 96500

Ni+2 ion Z value = 29.35/96500

                           = 3.041 * 10 -4

Pb +2 ion Z value = 103.6/96500

                         = 1.07 * 10-3

mass of Ni metal = Z * C * t

                          = 3.041 * 10-4 * 0.824 * 52.7 * 60

                          = 0.79233 g

mass of Pb metal = Z * C * t

                          = 1.07 * 10-3 * 0.790 * 34.7 *60

                         = 1.759 g

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