11. A large quantity of chemical energy is stored in a gummy bear, which is prim

Question

11. A large quantity of chemical energy is stored in a gummy bear, which is primarily sugar, C12H22O11. When a gummy bear is placed in molten KClO3, the sugar is oxidized according to the following thermochemical equation: If a gummy bear has an average mass of 0.5250 g and is 91.40% sugar, then how many whole gummy bears does It take to bring a cup of water (250.0 mL) at in Initial temperature of 20.0 degree C to the boiling point? The boiling point of water Is 100.0 degree C, the density of water (20 degree C) is 0.9982 g/mL, and the specific heat capacity of water Is 4.184 J/(g. degree C).

Explanation / Answer

Calculate the energy required first to bring the water to a boil

Q = mass x specific heat x temperature change.

The mass of the water is the volume * density = 250 ml x 0.9982 g/ml = 249.55 g
specific heat is given 4.184 J/g.oC
temperature change is 100C - 20C

Feeding all the values,

Q = 249.55 x 4.184 x 80 = 83529.376 J

number of moles of C12H22O11 = 83529.376 / 5488000 = 0.01522 mols

mass of sugar C12H22O11 = 0.01522 mol x 342.2965 g/mol = 5.21 g

mass of sugar in 1 gummy bear is 0.525 grams * 0.914 = 0.47985 g

nmber of gummy bears = total mass of sugar / mass of sugar per gummy bear = 5.21/0.47985 = 10.9 or 11

Thus, we would require 11 gummy bears in this case.

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