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D ezto.mheducation.com no Chapter 15 Inbox abby 7@g Gmail Mail Abigail R Looper

ID: 879337 • Letter: D

Question

D ezto.mheducation.com no Chapter 15 Inbox abby 7@g Gmail Mail Abigail R Looper Outlook Chegg.com Chapter 15 instructions help X Question 22 (of 3 Save & Exit Submit HE 22. 10.000 points 1 out of 3 attempts Assistance Be sure to answer all parts. Check My Work AG for the reaction View Hint View Qu H2(g) (g) Print is 2.60 kJ/mol at 25 C. Calculate AG, and predict the direction in which the reaction is Question Help spontaneous. The initial pressures are Report a Problem PH, -3.60 atm 1.5 atm PHI 1.75 atm AG kJ/mol The reaction is spontaneous in the forward direction. The reaction is spontaneous in the reverse direction. Cannot be determined. eBook & Resources References Multipart Answer Difficulty: Hard Section: 18.06

Explanation / Answer

delta G = delta Go + RTln Q

where delta Go = 2.6 X 1000 = 2600 J/mole
R = 8.314 J/K/mole
T = 25 + 273 = 298 K
Q = reaction quotient which has the same expression as equilibrium constant ...in this case Kp = [P(HI)]^2/ [P(H2)] [P(I2)]

where P(HI) = partial press of HI = 1.75 atm
P(I2) = 1.5 atm
P(H2) = 3.60 atm

delta G = 2600 + 8.314 X 298 X ln (1.75^2 / 3.60 X 1.5)

delta G = 2600 + 2477.572 X ln 3.218

delta G = 2600 + 2477.572 X (-0.567)

delta G =1194.235 J/mole or 1.194 kJ/mole

G is positive, the process proceeds spontaneously in reverse.