Need help for finding the rate at 35 degrees celcius and number 4. 2. The follow

Question

Need help for finding the rate at 35 degrees celcius and number 4.

2. The following data was collected for the first order reaction: 2 N2O5 (g) arrow 2 N2O4 (g) + O2(g) Determine graphically the energy of activation for the reaction. Show your calculations. 3. Using the information from question 2, calculate the rate constant at 35.0 degree C. Show your calculations. 4. Using the data from question 2, at what temperature (degree C) will the rate constant be 8.00 x 10^6 sec^-1? Show your calculations.

Explanation / Answer

We would use the relation,

ln(k2/k1) = Ea/R[1/T1-1/T2]

We know,

Take any reading from the table as k1, with Ea known, find k2

Calculations are thus shown below

Calculate Ea

ln(4.98 x 10^6 / 3.46 x 10^5) = Ea/8.314 [1/298 - 1/318]

Ea = 105052.2 J = 105.05 kJ

Find k2 at 35 oC (308 K)

Take reading for 25 oC

ln(k2/3.46 x 10^5) = 104990.02/8.314 [1/298 - 1/308]

k2 = 4.22 x 10^7

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