1. What is the value of q n k) when 21.9 g of liquid water is cooled from 0.00 d
ID: 881599 • Letter: 1
Question
1. What is the value of q n k) when 21.9 g of liquid water is cooled from 0.00 degree C to ice at -7.03 degree C?Please report your answer to the correct number of significant figures. 2. What is q, in kJ, for the process in which 21.9 g of liquid water at 100 degree C is converted into ice at 0.00 degree C? Please report your answer to the correct number of significant figures. 3. What is the value of q when 21.9 g of steam is heated from 100 degree C to 133 degree C? Please report your answer to the correct number of significant figures. 4. Which of the following statements are true? Water in its gaseous phase does not exhibit any hydrogen bonds between water molecules. The areas labeled b and d represent an increase in kinetic energy. The reaction that represents heat of vaporization is H2O(g)right arrow H2O(I). None of these (a-c) are correct All of these (a-c) are correctExplanation / Answer
1 . q = m s del T = 21.9 x 2.09 x 7.03/1000 = 0.32 kj
2 . q = m s del T = 21.9 x 4.18 x 100/1000 = 9.155 kj
3 . q = m s del T = 21.9 x 2 x (133-100)/1000 = 1.44 kj
1st and 2nd points are correct.
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