In 2009, a team from Northwestern University and Western Washington University r

Question

In 2009, a team from Northwestern University and Western Washington University reported the preparation of a new "spongy" material composed of nickel, molybdenum, and sulfur that excels at removing mercury from water. The density of this new material is 0.20 g/cm3, and its surface area is 1242 m2 per gram of material.

A)Calculate the volume of a 50.0 mg sample of this material.

B)Calculate the surface area for a 50.0 mg sample of this material.

c)A 10.0-mL sample of contaminated water had 7.748 mg of mercury in it. After treatment with 10.0 mgof the new spongy material, 0.001 mg of mercury remained in the contaminated water. What percentage of the mercury was removed from the water?

d)What is the final mass of the spongy material after the exposure to mercury?

Explanation / Answer

A) Convert 0.20 g/cm3 to mg

= 200 mg/cm3

use the formula density (d) = mass (m)/ volume (v)

volume (v) = 50.0 mg/ 200 mg/cm3

v = 0.25 cm3

B) convert 50 mg to gram = 0.05 g

then multiply with 1242

= 0.05 x 1240 = 62.1 m2

C) (7.748 / 7.747) x 100

= 99.99 %

D)

The mass of the Hg is 7.747 mg.
The mass of the spongy material 10.0 mg.
final mass = 7.747 + 10 =17.747 mg

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