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ID: 883735 • Letter: S
Question
Explanation / Answer
1)
molarity of CaCl2 = wt.of CaCl2*1000/(m.wt of CaCl2*volume of the solution)
= (110*10^-3) *1000)/(110.98*500)
= 0.0019M
NORMALITY = MOLARITY * CHARGE
= 0.0019*2
= 0.0038N
molarity of CaSO4 = wt.of CaSO4*1000/(m.wt of CaSO4*volume of the solution)
= (500*10^-3) *1000)/(136.14*500)
= 0.0073M
NORMALITY = MOLARITY * CHARGE
= 0.0073*2
= 0.0146N
THE TOTAL CONCNTRATION OF Ca^+2 = 0.0019+0.0073 = 0.0092 MOLAR
THE TOTAL CONCNTRATION OF Ca^+2 = (0.0038+0.0146) = 0.0184 NORMAL
THE TOAL CONCENTRATION OF Cl^-1 = 2*0.0019 = 0.0038 MOLAR
THE TOTAL CONVETRATION OF Cl^-1 = 2*0.0038 = 0.0076 NORMAL
THE TOTAL CONVETRATION OF SO4^-2 = 0.0073MOLAR
THE TOTAL CONVETRATION OF SO4^-2= 0.0146N
note:
CaCl2-----------------------------> Ca^+2 + 2 Cl^-1
CaSO4 -----------------------------> Ca^+2 + SO4^-2
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