How many grams of Ca are there in a sample of Ca that contains 5.88×10 23 atoms?

Question

How many grams of Ca are there in a sample of Ca that contains 5.88×1023atoms? _______ grams

Molar Mass

Moles

Mass in One Mole of Compound

g/mol

mol

g

g/mol

mol

g

Molar Mass xenon trioxide =____________ g/mol

Under certain conditions, the substance calcium carbonate can be broken down to form calcium oxide and carbon dioxide.
If 32.5 grams of calcium carbonate react to form 18.2 grams of calcium oxide, how many grams of carbon dioxidemust simultaneously be formed?

________________grams carbon dioxide

...

Molar Mass

...

Moles

...

Mass in One Mole of Compound

Xe

g/mol

mol

g

O

g/mol

mol

g

Explanation / Answer

we know that

moles = number of atoms / avagadro number

aslo

avagadro number = 6.023 x 10^23

so

moles of Ca = 5.88 x 10^23 / 6.023 x 10^23

moles of Ca = 0.976

2)

molar mass of Xe = 131 g/mol

molar mass of 0 = 16 g/mol

we know that

xenon trioxide is Xe03

so

molar mass of Xe03 = molar mass of Xe + ( 3 x molar mass of 0)

so

molar mass of Xe03 = 131 + ( 3 x 16)

molar mass of Xe03 = 179 g/mol

3)

the reaction is given by

CaC03 ---> Ca0 + C02

given

32.5 g of CaC03

we know that

moles = mass / molar mass

so

moles of CaC03 = 32.5 /100

moles of CaC03 = 0.325

moles of Ca0 = 18.2 / 56

moles of CaO = 0.325

now

consider the reaction

CaC03 --> CaO + Co2

we can see that

moles of CO2 formed = moles of CaO formed = 0.325

now

mass = moles x molar mass

so

mass of C02 = 0.325 x 44

mass of C02 = 14.3

so

14.3 grams of C02 is produced

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