Acid-Base Neutralization Part 1 Suppose there was 10 mL of diluted grape juice s

Question

Acid-Base Neutralization

Part 1

Suppose there was 10 mL of diluted grape juice solution in a test tube, the color is purple and the pH is 3.5:

1. If I add 15 drops of saturated citric acid solution to the test tube what will the color become what will the approximate pH be?

2. In a second test tube filled with the same type of grape juice, if I add 15 drops of saturated sodium bicarbonate solution, what color will the liquid become and what will the approximate pH be?

Part 2

If I used the tubes from the prior test would it take about the same amount of drops of the opposite solution to return it to its original color? Would this also return it to its original pH?

Explanation / Answer

Part 1. Grape juice tests.

1. Grape juice contains tartaric acid, malic acid and small amount of citric acid. The color of 10 mL of diluted grape juice in test tube is purple. After addition of 15 drops of saturated citric acid to it, the pH would drop to 3.0 from 3.5.

2. NaHCO3 is a base and would netralize the acid in the test tube. So when 15 drops of saturated NaHCO3 is added, the color will becomelight green. Appriximate pH would be towards basic side, that is around 7-8

Part 2. If we use the same test tube used in Part 1 and neutralize the base added by an acid. It would require the same amount of drops of the opposite solution to its original color. pH might differ due to increase in the solution volume.

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