conduct a chi square analysis to determine if these two genes are linked. if the
ID: 88756 • Letter: C
Question
conduct a chi square analysis to determine if these two genes are linked. if they are linked, calculate the map distance between the two genes.
Explanation / Answer
Part A)
Null hypothesis : The observed values are not deviating from 1:1:1:1 ratio.
Category
Green, Normal
Yellow, curling
green, curling
yellow, normal
Total
Observed values
117
115
78
80
390
Exptected Ratio
1
1
1
1
4
Exprected Values
97.5
97.5
97.5
97.5
Deviation
19.5
17.5
-19.5
-17.5
D^2
380.25
306.25
380.25
306.25
D^2/E
3.9
3.141026
3.9
3.141026
14.08205
X^2
14.08205
Degrees of freedom
4-1 = 3
Inference: The calculated chisquare value i.e.14.08 is higher than the table value i.e. 7.82 at 0.05 probability and 3 DF. Hence null hypothesis is rejected. Which indicates that the gene are linked.
Part B)
The map distance between genes = (Total frequency of recombinants / Total no of progeny) X 100
= (78+80 / 117+115+78+80) X 100 = (158/ 390) X 100 = 40.51
Category
Green, Normal
Yellow, curling
green, curling
yellow, normal
Total
Observed values
117
115
78
80
390
Exptected Ratio
1
1
1
1
4
Exprected Values
97.5
97.5
97.5
97.5
Deviation
19.5
17.5
-19.5
-17.5
D^2
380.25
306.25
380.25
306.25
D^2/E
3.9
3.141026
3.9
3.141026
14.08205
X^2
14.08205
Degrees of freedom
4-1 = 3
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.