Which one of these equations describes a retox reaction? 2Al(s) + 3H2SO4(aq) rig

Question

Which one of these equations describes a retox reaction? 2Al(s) + 3H2SO4(aq) rightarrow Al2(S04)3(aq) + 3H2(g) 2KBr(aq) + Pb(NO3)2(aq) rightarrow 2KNO3(aq) + PbBr2(s) CaBr2(aq) + H2SO4(aq) rightarrow CaS04(s) + 2HBr(g) H+(aq) + OH- (aq) rightarrow H2O(l) CO32- (aq) + HSO4 (aq) rightarrow HCO3- (aq) + SO42-(aq) Lithium metal dissolves in water to yield hydrogen gas and aqueous lithium hydroxide. What is the final concentration of hydroxide ions when 5.500 g of lithium metal is dropped into 750. mL of water? 1.06 M 0.528 M 2.11 M 0.792 M 0.943 M

Explanation / Answer

4. 2Al(s) + 3H2SO4(aq) ---> Al2SO4(aq) + 3H2(g)

Redox reaction : the reaction in which both oxidation and reduction takes place.

in the above,
oxidation : Al ----> Al3+ + 3e-

reduction : 3 H+ + 3e- --------> 3/2 H2

BUT all other reaction are ionic reactions.they are just participates in exchange of ions.

5.   

2Li(s) + 2H2O (l) ----> 2LiOH(aq) + H2(g)

No of moles of Li = 5.500/7 = 0.785 mole

No of moles of water = 750/18 = 41.67 mole

limiting reagent is Li

No of moles of LiOH produce = 0.785 mole

moles of water reacted = 41.67-0.785 = 40.885 mole

mass of water unreacted = 40.885*18 = 735.93 grams

volume of water unreacted = 40.885*18 = 735.93 ml

concentration of = n/Vin L = 0.785/0.73593 = 1.067 M

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