For the following reaction between Mohr\\\'s salt (iron as FeSO4(NH4)2SO4·6H2O)

Question

For the following reaction between Mohr's salt (iron as FeSO4(NH4)2SO4·6H2O) and potassium dichromate (dichromate as K2Cr2O7), determine the volume (in milliliters) of a 0.210 M solution of Mohr's salt that is needed to fully react with 0.0400 L of 0.210 M potassium dichromate. (The reaction is shown in its ionic form in the presence of a strong acid.)

For the following reaction between Mohr's salt (iron as FeSO4(NH4)2SO4 6H2O) and potassium dichromate (dichromate as K2Cr207), determine the volume (in milliliters) of a 0.210 M solution of Mohr's salt that is needed to fully react with 0.0400 L of 0.210 M potassium dichromate. (The reaction is shown in its ionic form in the presence of a strong acid.) 3+ Cr,O 6Fe+14H Number Mohr's salt volume = mL For the same reaction, what volume (in milliliters) of 0.210 M potassium dichromate is required to fully react with 0.0400 L of a 0.210 M solution of Mohr's salt? Number potassium dichromate volume = mL

Explanation / Answer

molCr2O7 = 0.210 mol/1L = 0.0400L = 8.4x10-3 mol

6mol Fe2+ -------- 1 mol Cr2O7

X mol Fe2+-------- 8.4x10-3 mol Cr2O7

X = 6/1 x 8.4x10-3 = 0.0504 mol Fe2+

mL = 1000 mL /0.210 mol x 0.0504 mol = 240 mL Fe2+

molFe2+ = 0.210 mol/1L = 0.0400L = 8.4x10-3 mol

6mol Fe2+ -------- 1 mol Cr2O7

8.4x10-3 mol Fe2+-------- X mol Cr2O7

X = 1 x 8.4x10-3 /6 = 1.4 x 10-3 mol Cr2O7

mL = 1000 mL /0.210 mol x1.4 x 10-3 mol = 6.666 mL Cr2O7

Mohr's salt K2Cr2O7 Concentration (M) 0.210 0.210 Volume (L) 0.0400 ?

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