If 250 cal of heat were added to 43.8 g of Al at 22.5 degrees Celsius, what is f

Question

If 250 cal of heat were added to 43.8 g of Al at 22.5 degrees Celsius, what is final temperature of the aluminum? I know heat=(mass)(final temp-initial temp)
How do I know what formula to use for this though?
If 250 cal of heat were added to 43.8 g of Al at 22.5 degrees Celsius, what is final temperature of the aluminum? I know heat=(mass)(final temp-initial temp)
How do I know what formula to use for this though?
I know heat=(mass)(final temp-initial temp)
How do I know what formula to use for this though?
How do I know what formula to use for this though?

Explanation / Answer

We will use the formula,

q = mCp(Tf-Ti)

where,

q = 250 cal = 1046.7 J

m = 43.8 g

Cp for Al = 0.9 J/g.oC

Ti = 22.5 oC

Tf = unknown

Feed values,

1046.7 = 43.8 x 0.9 (Tf-22.5)

Tf = 49.05 oC

So the final temperature would of the aluminum would be 49.05 oC

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