Molarity of standard NaOH solution: x/1 H 2/3 Unknown + 2/3 NaOH -> 2/3 H2O +Na
ID: 895276 • Letter: M
Question
Molarity of standard NaOH solution: x/1 H 2/3 Unknown + 2/3 NaOH -> 2/3 H2O +Na 2/3 Acetate
Unknown Acid code and number of reactive hydrogens: H+3
14. Average your three formula masses to get your final answer for the formula mass of
your unknown acid.
15. Calculate the percent deviation for each of your three formula masses.
16. AgBr reacts with Na2S2O3 according to the following equation:
AgBr (s) + 2 Na2S2O3 (aq) ==> Na3Ag(S2O3)2 (aq) + NaBr (aq)
How many milliliters of 0.0138 M Na2S2O3 are needed to dissolve 0.250 g of AgBr?
17. Write the balanced double displacement reaction for Pb(NO3)2 reacting with NaCl.
How many milliliters of 0.750 M Pb(NO3)2 are required to react completely with 525 mL of 2.25 M NaCl?
Vinegar: Titration 1 Titration 2 Tirtration 3 Initial V of Acid .01 mL 5.56 mL 11.32 mL Final V of Acid 5.56 mL 10.71 mL 16.02 mL Inital V of Base .01 mL 27.12 mL 3.01 mL Final V of Base 22.23 mL 44.71 mL 24.90 mLExplanation / Answer
16.
0.250 g AgBr / 187.77 g/mol = 0.00133 mol AgBr
The molar ratio AgBr / Na2S2O3 is 1:2
(0.0138 mol/L Na2S2O3 x V Na2S2O3 L) / 2 = 0.00133 mol AgBr
V Na2S2O3 = 0.192 L =192 mL
17.
Pb(NO3)2 + 2NaCl = 2NaNO3 + PbCl2
The Ratio Pb(NO3)2 / NaCl is 1:2
V Pb(NO3)2 = (0.525 L x 2.25 mol/L / 2 )/ 0.750 mol/L =
= 0.7875 L = 787.5 mL
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