I need help how do I approach this? mas-ransfor coeficient ix owng 0016 W, ams W
ID: 895427 • Letter: I
Question
I need help how do I approach this?
Explanation / Answer
30 m x 15 m x 0.017 m/s = 7.65 m3 /s = 7650 L/s are deplaced from the paste surface
At the paste surface the concentrtion of vapour is 0.002 mol/L, then
7650 L/s x 0.002 mol/L = 15.3 mol water /s are removed or
15.3 mol x 18 g/mol = 275.4 g /s are removed or
275.4 g /s x 1 g/mL = 275.4 mL/s are removed or
275.4 mL/s = 0.2754 L/s are removed or
0.2754 L/s x 60 s/min = 16.5 L/min are removed.
The minimum condition is fulfilled: 16.5 L/min > 9.5 L/min
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