In step 5, of the experiment, a student accidentally added 2.0g of Mg metal inst
ID: 896442 • Letter: I
Question
In step 5, of the experiment, a student accidentally added 2.0g of Mg metal instead of Zn, to react with 5.0g of CuSO4 . How will this affect the result of the experiment?
The copper (II) sulfate solution would react with the Mg, because Cu is less active than Mg. However, not all the copper (II) sulfate was reacted to form Cu.
The copper (II) sulfate solution would react with the Mg, because Cu is less active than Mg. However, the excess Mg would not react with the 6M HCl because Mg is less active than hydrogen.
The copper (II) sulfate solution would not react with the Mg. This is because Cu is more active than Mg.
There will be no effect in the final result, all the copper (II) sulfate will be converted to Cu.
A.The copper (II) sulfate solution would react with the Mg, because Cu is less active than Mg. However, not all the copper (II) sulfate was reacted to form Cu.
B.The copper (II) sulfate solution would react with the Mg, because Cu is less active than Mg. However, the excess Mg would not react with the 6M HCl because Mg is less active than hydrogen.
C.The copper (II) sulfate solution would not react with the Mg. This is because Cu is more active than Mg.
D.There will be no effect in the final result, all the copper (II) sulfate will be converted to Cu.
Explanation / Answer
you should follow the electrochemical series
Ans. The copper (II) sulfate solution would react with the Mg, because Cu is less active than Mg. However, not all the copper (II) sulfate was reacted to form Cu.
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