If a polymer is prepared from 0.52 g of acrylic acid, and 0.2 mL of 8.0 M NaOH,

Question

If a polymer is prepared from 0.52 g of acrylic acid, and 0.2 mL of 8.0 M NaOH, what will the mass of the "dry" polymer be after all of the water is removed? Assume all reactions go to completion.

Hint: You may want to construct a BCA table to determine the outcome of the neutralization step.

2)If a polymer with a dry mass of 1.7 has a mass of 343.9 after swelling in deionized water, what is the swelling ratio?

3) How much solid sodium chloride would you need to make 87.3 mL of a 8.31% (mass %) NaCl solution? Assume the density of water is 1.00 g/mL, and that the density of the solution is close to that of pure water.

Explanation / Answer

3) Mass of solution of NaCl = volume*densiity = 87.3 g

mass of NaCl required = (8.31/100)*87.3 = 7.254 g

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