Hi, can someone help me? I\'m having trouble with parts B and D... Part A. Enter

Question

Hi, can someone help me? I'm having trouble with parts B and D...

Part A. Enter the equation for the formation of RbCl(s) from its respective elements in their standard states.

Answer:

2Rb(s)+Cl2(g)2RbCl(s)

Part B. What is the value of Hf for the formation of 1 mol of RbCl(s)?

Part C. Enter the chemical equation for the formation of Ca(NO3)2(s) from its respective elements in their standard states.

Answer:

Ca(s)+N2(g)+3O2(g)Ca(NO3)2(s)

Part D. What is the value of Hf for this reaction?

2Rb(s)+Cl2(g)2RbCl(s)

Explanation / Answer

Part B:

Satandard Enthalpy of Formation of Rb = 0

Satandard Enthalpy of Formation of Cl2 = 0, so the enthalpy of formation of RbCl is a standard given value.

Satandard Enthalpy of Formation of RbCl is = - 430.5 kJ / mole

Part D:

Ca is a solid at ambient temps/pressure. Oxygen is O2(g) and Nitrogen is N2(g)

Therefore it would be Ca(s) + N2(g) + 3O2(g) --> Ca(NO3)2(s)

Satandard Enthalpy of Formation of Ca(NO3)2(s) = -938.39 KJ

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.