xplain your Sodium hydrogen carbonate, NaHCO, is a base used in several commerci
ID: 898576 • Letter: X
Question
xplain your Sodium hydrogen carbonate, NaHCO, is a base used in several commercial antacids. The overall reaction with HCl is: HCl (aq) + NaHCO3(aq) NaCl(aq) + H20() + CO2(g) A tablet, which had a mass of 1.213 g, was pulverized and 0.613 g were dissolved in 25.00 mL of 0.220 M HCI. The titration of this solution with 0.1615 M NaOH required 26.30 mL to reach the phenolphthalein end point. The reaction of NaOH and HCl is: IS: HCI(aq) + NaOH(aq) NaCl(aq) + H2O(1) a) Determine the moles of HCI that were added to the sample analyzed. volumedi) volumec) volume as.eonL-O O35Explanation / Answer
Mass of a tablet= 1.213 g
wt. of sample taken for analysis= 0.613 g
Con. of HCl= 0.22 M; Volume of HCl= 25.0 mL
Con. of NaOH= 0.1615 M; volume of NaOH=26.30 mL
use (MV)HCl= (MV)NaOH
In absence of sample, 25.0 mL of 0.22 M HCl required
VNaOH= (MV)HCl / MNaOH= (0.22 x 25.0)/ 0.1615= 34.05 mL of NaOH solution.
But, In presence of sample, volume of NaOH required is 26.30 mL.
thus, the 34.05-26.30= 7.75 mL of NaOH
use (MV)HCl= (MV)NaOH
(V)HCl= (MV)NaOH/ MHCl= (0.1615 x 7.75)/ 0.22= 5.69 mL
thus, voume of NaHCO3 consumed is 5.69 mL of HCl,
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