Titanium occurs in the magnetic mineral ilmenite (FeTiO3), which is often found

Question

Titanium occurs in the magnetic mineral ilmenite (FeTiO3), which is often found mixed up with sand. The ilmenite can be separated from the sand with magnets. The titanium can then be extracted from the ilmenite by the following set of reactions:

FeTiO3(s)+3Cl2(g)+3C(s)3CO(g)+FeCl2(s)+TiCl4(g)TiCl4(g)+2Mg(s)2MgCl2(l)+Ti(s)
Suppose that an ilmenite-sand mixture contains 20.2 % ilmenite by mass and that the first reaction is carried out with a 91.2 % yield.

If the second reaction is carried out with an 86.2 % yield, what mass of titanium can be obtained from 1.30 kg of the ilmenite-sand mixture?

Explanation / Answer

FeTiO3(s)+3Cl2(g)+3C(s)3CO(g)+FeCl2(s)+TiCl4(g)

TiCl4(g)+2Mg(s)2MgCl2(l)+Ti(s)

20.2% of ilminite by mass

yield 1 of 91.2%

yield 2 86.2%

what is the mass obtained of Titanium if we get 1.30 kg of the ilminite sand mix

Lets do the analysis

find the amount of ilmenite which is 20.2%

1.30kg*0.202 = 0.2626 kg of Ilmenite (FeTIO3)

% of Ti in Ilmenite

MW of FeTiO3 = 151.7

MW of Ti = 47.8

% of Ti in Ilmenite = 47.8/151.7= 31.5%

0.2626 *0.315 = 0.0827 kg of Ti are present

1 mol of FeTiO3 --> 1 mol of TiCl4

but onl y 91.2% of the yield is true

0.0827 *0.912 = 0.0754 kg of Ti will react

Now, the second will only react 86.2%

0.0754*0.862 = 0.065 kg of Ti

That will be the amount of Titanium in the final sample

Therefore, the yield

% yield = 0.065 kg / 1.30 kg* 100% = 5%

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