what is the nucleophile and what is the substrate for this reaction: 1-octanol +
ID: 902142 • Letter: W
Question
what is the nucleophile and what is the substrate for this reaction: 1-octanol + HBR -->BromooctaneAnd what are the starting weight of the reactions? 2.5 ml of 48% hydrobromic acid, 1.5 ml of 1-octanol. 1-octanol density =0.825 g/ml, 1-bromooctane density = 1.118 g/ml. M/W for 1-octanol = 130.2, and for 1-bromooctane =193.1. what is the nucleophile and what is the substrate for this reaction: 1-octanol + HBR -->Bromooctane
And what are the starting weight of the reactions? 2.5 ml of 48% hydrobromic acid, 1.5 ml of 1-octanol. 1-octanol density =0.825 g/ml, 1-bromooctane density = 1.118 g/ml. M/W for 1-octanol = 130.2, and for 1-bromooctane =193.1. what is the nucleophile and what is the substrate for this reaction: 1-octanol + HBR -->Bromooctane
And what are the starting weight of the reactions? 2.5 ml of 48% hydrobromic acid, 1.5 ml of 1-octanol. 1-octanol density =0.825 g/ml, 1-bromooctane density = 1.118 g/ml. M/W for 1-octanol = 130.2, and for 1-bromooctane =193.1.
Explanation / Answer
HBr is the Nucleophile
1-octanol is the Substrate
Starting weight of reaction = weight of HBr in 2.5 mL of 48% HBr + weight of 1.5 mL of 1-octanol
Weight of HBr in 2.5 mL of 48% HBr = 2.5 x (48 / 100) = 1.2 g
Weight of 1.5 mL of 1-octanol
Volume of 1-octanol = 1.5 mL
Density = 0.825 g/mL
=> Mass = Density x Volume
=> Mass = 0.825 x 1.5 = 1.2375 g
=> Starting weight of reactions = 1.2 + 1.2375 = 2.4375 g
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