1.Hydrogen gas can be produced in the laboratory through reaction of magnesium m

Question

1.Hydrogen gas can be produced in the laboratory through reaction of magnesium metal with hydrochloric acid: Mg+ 2HCl-> MgCk + H2
2. What volume, in liters, of H2 at 25 degree Celsius and 0.975atmosphere pressure can be produced from reaction of 6.5 g of Mg with an excess of HCl? 1.Hydrogen gas can be produced in the laboratory through reaction of magnesium metal with hydrochloric acid: Mg+ 2HCl-> MgCk + H2
2. What volume, in liters, of H2 at 25 degree Celsius and 0.975atmosphere pressure can be produced from reaction of 6.5 g of Mg with an excess of HCl? Mg+ 2HCl-> MgCk + H2
2. What volume, in liters, of H2 at 25 degree Celsius and 0.975atmosphere pressure can be produced from reaction of 6.5 g of Mg with an excess of HCl?

Explanation / Answer

Mg+ 2HCl-> MgCl2 + H2

Number of moles of Mg = 6.5/24.3 = 0.2674 moles

Number of moles of HCl = 2 x number of moles of Mg = 0.5349 moles

So amount of HCl = 0.5349 x 36.5 = 19.52 g

Since 2 mol of HCl is needed to react with 1 mol of Mg, so Mg is clearly the limiting reagent

No. of mol of Mg reacted= 0.2674 moles

Thus, no. of mol. of H2 produced= 0.2674 moles

Mass of H2 produced = 0.2674 x 2 = 0.5348 gram

PV = n R T

0.975 x V = 0.2674 x 0.0821 x 298

V = 6.709 mL

= 0.006709 L

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