A cylinder, with a piston pressing down with a constant pressure, is filled with

Question

A cylinder, with a piston pressing down with a constant pressure, is filled with 2.20 moles of gas (n1), and it's volume is 46.0 L (v1). 0.400 mole gas leak out, and the pressure and temperature remain the same, what is the final volume of the gas inside the cylinder?
V2= ? L
B.) A sample of gas and a cylinder as the example and part has initial value of 42.0 L, and you have determined that it contains 2.00 moles of gas. The next day you noticed that some of the gas has leaked out. The pressure and temperature remain the same, but the Byam has changed to 10.5 L. How many moles gas (n2) remain in the cylinder ?
N2= ? Mole

A cylinder, with a piston pressing down with a constant pressure, is filled with 2.20 moles of gas (n1), and it's volume is 46.0 L (v1). 0.400 mole gas leak out, and the pressure and temperature remain the same, what is the final volume of the gas inside the cylinder?
V2= ? L
B.) A sample of gas and a cylinder as the example and part has initial value of 42.0 L, and you have determined that it contains 2.00 moles of gas. The next day you noticed that some of the gas has leaked out. The pressure and temperature remain the same, but the Byam has changed to 10.5 L. How many moles gas (n2) remain in the cylinder ?
N2= ? Mole


V2= ? L
B.) A sample of gas and a cylinder as the example and part has initial value of 42.0 L, and you have determined that it contains 2.00 moles of gas. The next day you noticed that some of the gas has leaked out. The pressure and temperature remain the same, but the Byam has changed to 10.5 L. How many moles gas (n2) remain in the cylinder ?
N2= ? Mole

Explanation / Answer

Answer - A) We are given, moles , n1 = 2.20 moles , V1 = 46.0 L , 0.400 mole gas leak out means

The final moles inside the cylinder, n2 = 2.20-0.400 = 1.80 moles , V2 = ?

We know at constant temp and pressure volume is directly proportional to the amount of gas means moles

V1/n1 = V2 /n2

V2 = V1 * n2 / n1

      = 46.0 L * 1.80 mole / 2.20 mole

      = 37.6 L

B) We are given, n1 = 2.00 moles , V1 = 42.0 L ,

Changed V2 = 42.0-10.5 = 31.5 L

We know at constant temp and pressure volume is directly proportional to the amount of gas means moles

V1/n1 = V2 /n2

n2 = V2 * n1 / V1

      = 31.5.0 L * 2.00 mole / 46.0 L

      = 1.37 mole

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.