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Answer the following true/false questions regarding net ionic equations. You nee

ID: 905638 • Letter: A

Question

Answer the following true/false questions regarding net ionic equations. You need to write a net ionic equation for every test where a precipitate formed. Refer the page in experiment 5 on "How to Write Net Ionic Equations" for help answering these questions. To write net ionic equations you need to follow some simple steps for this experiment:

1. Write down the reactants

2. Now put an arrow and write down the products knowing that opposites attract:

3. Next cross out the cations or anions that are always soluble (sodium, nitrate, ammonium, potassium, hydrogen ions are nearly always soluble). Cross ions that are combined with these soluble ions in the product.

4. Rewrite the equation with what is left over.

5. Make sure charge on the product is zero. Change the number of cations or anions present so this is true.

6. Make sure the equation is balanced. That's the net ionic equation.

Keep in mind that nitrate, ammonium, carbonate, hydroxide, and phosphate ions are polyatomic ions and do not break apart in these precipitation reactions.

Also ammonia in a 1M ammonium hydroxide solution reacts with water to form ammomium ion and hydroxide ion. There is almost no ammonia present in this reagent, so....the reactants will be ammonium and hydroxide ions for this solution.

True & False:
( ) Ammonium, sodium, and nitrate are all spectator ions.
( ) If you mix potassium iodide and silver nitrate the precipitate that forms will be potassium nitrate.
( ) In 1M ammonium hydroxide solution, hydroxide can react with some cations to form precipitates.
( ) Ammonium nitrate will react with sodium carbonate to form sodium nitrate (a precipitate).
( ) Hydroxide, carbonate, and phosphate are always spectator ions.

Explanation / Answer

(1) ammonia in a 1M ammonium hydroxide solution reacts with water to form ammomium ion and hydroxide ion    (TRUE)

(2). There is almost no ammonia present in this reagent, so....the reactants will be ammonium and hydroxide ions for this solution. (TRUE)

(3) In 1M ammonium hydroxide solution, hydroxide can react with some cations to form precipitates.(TRUE)

(4)Hydroxide, carbonate, and phosphate are always spectator ions.(False)

(5)If you mix potassium iodide and silver nitrate the precipitate that forms will be potassium nitrate.(False)

(6) Ammonium nitrate will react with sodium carbonate to form sodium nitrate (a precipitate).(False)

(7) If you mix sodium sulfate and barium nitrate the precipitate that forms will be barium sulfate.(True)

explanation:

(7) Na2SO4 (aq) + Ba(NO3)2 (aq) ---------------------> BaSO4 (s) + 2NaNO3 (aq)

      here BaSO4 is precipitate                                                            

(6) NH4NO3 (aq) + Na2CO3 (aq) --------------------> (NH4)2CO3 (s) + 2NaNO3 (aq)

here (NH4)2CO3 is precipitate

(5) KI (aq) + AgNO3 (aq) --------------------> AgI(s) + KNO3(aq)

here AgI precipitate

note : total data is so confusing finally i got an correct order. if you have any doubts post comment to me

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