Complete the two reduction half reactions for the cell shown at the right, and s

Question

Complete the two reduction half reactions for the cell shown at the right, and show the correct line notation for the cell by dragging the labels into the correct position. (The electrode on the left is the anode, the one on the right is the cathode.)

Map sapling learning mplete the two reduction half reactions for the cell shown at the ht, and show the correct line notation for the cell by dragging the labels into the correct position. (The electrode on the left is the anode the one on the right is the cathode.) Anode half reaction Co Cu + 2OH Cathode half reaction + 2 2OH Cu(OH)zS -Co(OH)2(s) Line notation KOH(aq) KOH(aq) Cols)

Explanation / Answer

Co2+ + 2 e <---> Co(s) 0.28

Cu2+ + 2 e <---> Cu(s) +0.337

The most positive will be reduced, the most negative will be oxidized, therefore:

Co(s)<--->Co2+ + 2 e  +0.28

Cu2+ + 2 e <---> Cu(s) +0.337

The cells:

Co(OH)2<--->Co2+ + 2 e  +0.28

Cu2+ + 2 e <---> Cu(OH)2 +0.337

Cell notation

Co(s)//Co+2(aq) and Cu2+(aq)//Cu(s)

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