A cell consists of a gold wire and a saturated calomel electrode (S.C.E.) in a 0

Question

A cell consists of a gold wire and a saturated calomel electrode (S.C.E.) in a 0.120 M AuNO3 solution at 25 °C. The gold wire is connected to the positive end of a potentiometer, and the S.C.E. is connected to the negative end of the potentiometer. What is the half-reaction for the Au electrode?

Ignoring activities, if the standard reduction potential for the above reaction is E0 = 1.69 V, what is potential of the gold electrode?

The reduction potential for the saturated calomel electrode is E = 0.241 V. What is the cell voltage?

Explanation / Answer

1)

Au +   + 1e-   ------> Au

E=E0-(0.05916/n) x log(1/[Au+])

E=1.69-(0.05916/1) x log 1/0.180

E=1.6459 V

2)

E cell = 1.6459-0.241

        = 1.404 V

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