q5 and 6 and 7 plz Write a balanced net ionic equation for the reaction between

Question

q5 and 6 and 7 plz Write a balanced net ionic equation for the reaction between sodium hydroxide and copper (II) ions that occurred in step 4 of the procedure. In your equation, indicate the physical states of all the reactants and products. 6. Write a balanced equation for the reaction that occurred in step 5 of the procedure. Indicate the physical mates of all reactants and products (Hints: The only reactant is copper (II) hydroxide. The products an copper (II) oxide and water.) 7. Write balanced molecular and net ionic equations for the reaction that occurred in step 8 of the procedure. Indicate the physical states of all reactants and products. (Hints: Copper (II) oxide, like all metallic oxides, reacts like a strong base. Therefore. it will react with an acid to produce water and a Salt,)

Explanation / Answer

5. Balanced net ionic equation: Net ionic equations are equations that show only the soluble, strong electrolytes reacting (these are represented as ions) and omit the spectator ions, which go through the reaction unchanged. The balanced net ionic equation between Cu2+(say CuSO4) and NaOH will be..

Cu2+ (aq) + 2OH- (aq) = CuO (s) + H2O (l)

6. The balanced molecular equation is:

CuSO4(aq) + 2 NaOH(aq) = CuO(s) + H2O(l) + Na2SO4(aq)

From this we get,

Cu(aq) + SO4(aq) + 2Na+(aq) + 2OH-(aq) = CuO(s) + H2O(l) + SO4(aq) + 2Na+(aq)

or, Cu(OH)2 (aq) = CuO(s) + H2O(l) ....[this is the balanced equation]

7. Balanced molecular equation:

CuO(s) + 2HCl (aq) = CuCl2 (aq) + H2O(l)

Net ionic equation:

CuO(s) + 2H+(aq) + 2Cl-(aq) = Cu2+(aq) + 2Cl-(aq) + H2O(l)

or, CuO(s) + 2H+(aq) = Cu2+(aq) + H2O(l)

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