The concentration of the initial stock solution is 3.00 M. The first dilution is

Question

The concentration of the initial stock solution is 3.00 M. The first dilution is made by measuring 10.00 mL with a volumetric pipet and diluting in a 100 mL volumetric flask. What is the concentration of the first solution?

The second solution is made by measuring 25.00 mL of the first solution and diluting in a 100 mL volumetric flask. What is the concentration of the second solution?

The third solution is made by measuring 50.00 mL of the second solution and diluting in a 250 mL volumetric flask. What is the concentration of the third solution?

The fourth solution is made by measuring 1.00 mL of the third solution and diluting in a 500 mL volumetric flask. What is the concentration of the fourth solution?

Explanation / Answer

It is calculated by using the formula

Final Concentration = (Stock concentration x Stock volume)/Final Volume

In First Dilution

Stock concentration = 3.00 M

Stock Volume = 10 mL

Final Volume = 100 mL

So Final Concentration = (3 x 10)/100

Final Concentration of first dilution = 0.3 M or 300 mM

In Second solution

Stock concentration from first dilution = 0.3 M

Stock Volume = 25 mL

Final Volume = 100 mL

So Final Concentration = (0.3 x 25)/100

Final Concentration of Second dilution = 0.075 M or 75 mM

In Third solution

Stock concentration from second dilution = 0.075 M

Stock Volume = 50 mL

Final Volume = 250 mL

So Final Concentration = (0.075 x 50)/250

Final Concentration of Third dilution = 0.015 M or 15 mM

In Fourth solution

Stock concentration from Third dilution = 0.015 M

Stock Volume = 1 mL

Final Volume = 500 mL

So Final Concentration = (0.015 x 1)/500

Final Concentration of Third dilution = 0.00003 M or 0.03 mM

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