The concentration of the initial stock solution is 3.00 M. The first dilution is

Question

The concentration of the initial stock solution is 3.00 M. The first dilution is made by measuring 10.00 mL with a volumetric pipet and diluting in a 100 mL volumetric flask. What is the concentration of the first solution?

The second solution is made by measuring 25.00 mL of the first solution and diluting in a 100 mL volumetric flask. What is the concentration of the second solution?

The third solution is made by measuring 50.00 mL of the second solution and diluting in a 250 mL volumetric flask. What is the concentration of the third solution?

The fourth solution is made by measuring 1.00 mL of the third solution and diluting in a 500 mL volumetric flask. What is the concentration of the fourth solution?

Explanation / Answer

a)
10 mL of 3 M solution was diluted to 100 mL
To find concentration of 1st solution use:
C0*V0 = C1*V1
3*10 = C1*100
C1 = 0.3 M
Answer: 0.3 M

b)
25 mL of 0.3 M solution was diluted to 100 mL
To find concentration of 2nd solution use:
C1*V1 = C2*V2
0.3*25 = C2*100
C2 = 0.075 M
Answer: 0.075 M

c)
50 mL of 0.075 M solution was diluted to 250 mL
To find concentration of 3rd solution use:
C2*V2 = C3*V3
0.075*50 = C3*250
C3 = 0.015 M
Answer: 0.015 M

d)
1 mL of 0.015 M solution was diluted to 500 mL
To find concentration of 4th solution use:
C3*V3 = C4*V4
0.015*1 = C4*500
C4 = 3*10^-5 M
Answer: 3*10^-5 M

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