Ethyl butyrate, CH3CH2CH2CO2CH2CH3, is an artificial fruit flavor commonly used

Question

Ethyl butyrate, CH3CH2CH2CO2CH2CH3, is an artificial fruit flavor commonly used in the food industry for such flavors as orange and pineapple. Its fragrance and taste are often associated with fresh orange juice, and thus it is most commonly used as orange flavoring. It can be produced by the reaction of butanoic acid with ethanol in the presence of an acid catalyst (H+):

CH3CH2CH2CO2H(l)+CH2CH3OH(l)H+CH3CH2CH2CO2CH2CH3(l)+H2O(l)

Part A

Given 7.60 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100% yield?

Express your answer in grams to three significant figures.

Part B

A chemist ran the reaction and obtained 5.75 g of ethyl butyrate. What was the percent yield? Express your answer as a percent to three significant figures.Part C The chemist discovers a more efficient catalyst that can produce ethyl butyrate with a 78.0% yield. How many grams would be produced from 7.60 g of butanoic acid and excess ethanol?

Express your answer in grams to three significant figures.

Part C

The chemist discovers a more efficient catalyst that can produce ethyl butyrate with a 78.0% yield. How many grams would be produced from 7.60 g of butanoic acid and excess ethanol?
Express your answer in grams to three significant figures.

Explanation / Answer

Part A:

mol butanoic acid= 7.6g/88g/mol= 0.086 mol

1 mol butanoic acid produces 1 mol of ethyl butyrate, so 0.086 mol butanoic acid produces 0.086 mol ethyl butyrate.

mass ethyl butyrate= 0.086 mol x 116g/mol= 9.98g

Part B:

% yield= amount obtained/theoretical yield x 100= 5.75g/9.98g x100= 57.6%

Part C:

78%= amount obtained/9.98g x 100 ----> amount obtained= 7.78 g

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