1 - The molar solubility of cadmium hydroxide,Cd(OH2) is 1.842 x 10^-5M. What is

Question

1 - The molar solubility of cadmium hydroxide,Cd(OH2) is 1.842 x 10^-5M. What is the Ksp value of cadmium hydroxide?

2- What volume of sodium thiosulfate and water are needed to make an approximate 0.10M solution starting with 1.0M sodium thiosulfate solution?

(3) Determination of molar solubility and Ksp of Ca(OH2) Titration data

Temperature of calcium hydroxide solution = 25 Degrees celcius

Concentration of Hydrochloric acid

4- Concentration of Ca2+ ions in the saturated Ca(OH2) solution?

5 - Concentration of hydroxide (OH-) ions in the saturated Ca(OH2) solution?

6- Solubility of Ca(OH2)?

7- Calculated value of Ksp for Ca(OH2)?

Trial 1 Trial 2 Trial 3 Volume HCl Volume HCl Volume HCl Final Buret Volume 10.6 21.2 32 Intial Buret Volume 0 10.6 21.2 Total Buret Volume 10.6 31.8 53.2

Explanation / Answer

there are seven questions.

i am solving 2 questions,

please post the remaining questions separately.thanks

1) Molar solubility Cd(OH)2 is 1.842 x 10-5M

Cd(OH)2 --------->   Cd+2   + 2 OH-

Ksp = 4 S3 = 4 x (1.842 x 10-5 )3 = 2.49x10-14

2)    M final = M1V1 /(V1+Vwater )

       0.1     = 1xV1/(V1 +Vwater )

Ratio of V1/Vwater = 1/9

3)

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