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XWhat is the electron MyScrapNooK"*EZ Crea MyScrapNoole . ,k EZ Create Facebook tmal cebook Email iversity of florida apply b university of florida apply. See What's Hot 1/1/2014WildTangent Games fo... Signed in as Rachel Belmont bobp nergy Resources a previous 6 of 7 Part A Calculate the amount of energy released in the formation of one mole of BeS bonds (not lattice energy) The radius of the berylium ion is 0.31 À and the radius of the sulide ion is 1.84 A Note that 1 A-10 10m Express your answer with the appropriate units to three significant figures Energy released: | 1.86. 102 Unis Give Up Review Part

Explanation / Answer

Part A : we have the formula,

Energy released in J = kq1q2/(r1+r2)

with,

k = constant = 2.31 x 10^-28 J.m from literature

q1 = 2

q2 = 2

r1 = 0.31 x 10^-10 m

r2 = 1.84 x 10^-10 m

we get,

energy released in the formation of 1 mole of BeS = 2.31 x 10^-28 x 2 x 2/(0.31 x 10^-10 + 1.84 x 10^-10)

= 4.30 x 10^-18 J

Part B : The order of ionic compounds in decreasing amount of energy released in lattice formation would be,

InN > BaO > LiCl > KI

InN we have triple bond beteen In and N (+3 oxidation states) so high energy. BaO we have +2 oxidation states so high energy. Smaller atoms would have stronger attraction so LiCl next and least for KI

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