This is a problem in an organic chemistry lab report that I\'m not quite sure ho

Question

This is a problem in an organic chemistry lab report that I'm not quite sure how to go about doing. A sample of usnic acid dissolved in chloroform is in a polarimeter (the specific rotation of chloroform is +488 degrees). The path length in the polarimeter is 1dm, and the observed rotation is +2.07
From this, do I find the concentration of usnic acid dissolved in chloroform? This is a problem in an organic chemistry lab report that I'm not quite sure how to go about doing. A sample of usnic acid dissolved in chloroform is in a polarimeter (the specific rotation of chloroform is +488 degrees). The path length in the polarimeter is 1dm, and the observed rotation is +2.07
From this, do I find the concentration of usnic acid dissolved in chloroform? A sample of usnic acid dissolved in chloroform is in a polarimeter (the specific rotation of chloroform is +488 degrees). The path length in the polarimeter is 1dm, and the observed rotation is +2.07
From this, do I find the concentration of usnic acid dissolved in chloroform?

Explanation / Answer

specific rotation = observed rotation / (l * C)

C = observed rotation / (specific rotation * l)

C= 2.07 / ( 488-360) *1

C = 0.01617 g / mL

here the angle of rotation 488. but we have 360 on agle scale so we have to subtract from from 488, then angle rotation = 488 - 360 = 128.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.