Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

iPad 8:08 PM 59% ent.com ¢ + mail-attachment Dr. Chuck Missler-Beyond Coinciden

ID: 921102 • Letter: I

Question

iPad 8:08 PM 59% ent.com ¢ + mail-attachment Dr. Chuck Missler-Beyond Coinciden | Jackson State University-Students Mail | Student Date Instructor: Dr. Tetiana Zubatiuk 1 of 7 ADDITIONAL ASSIGNMENTS SUM OF POINTS: /20 A cylinder contains 2.S0L of air at a pressure of 5.00 atmospheres. At what volume, will the air exert a 1pressure of 1 atmosphere, at the same temperature? 0.500L 7.50L 12.5L 2.00L 10.0L A student obtained the following data using the procedure in the experiment Corrected volume of the flask 955.0 mL Perform necessary calculations to fill in the blanks in the following table: Syringe Barometric pressure = 950.0 cm H2O System Volume, mL Height of H:O System Pressure, cm H:O P-V cm-mL Volume, mL 50.0 0.0 41.3 Sketch and explain the type of graphs you would get by plotting pressure, P, against volume, V of a gas [put V on x-axis, P on y-axis]. Use the graph paper Straight line Hyperbole curve 3Calculate the increase in volume when 2.00L of gas at 20.0 C is heated to 353K Tz, K

Explanation / Answer

P1= 5 atm

From P1V1= P2V2

Where P2= 1 atm

V2= P1V1/P2= 5*2.5 =12.5 L     

950 cm water =955nml

1.9 cm = 1.9*955/950= 1.91ml

Presssure = 1.9*950/955=1.89 PV= 1.9*1.91=3.63 cm ml

41.3 cm correspond to 41.3*955/950= 41.52ml

PV= 41.52*41.3= 1714.176

The curve between P and V is hyperobolic P inversly proporitonal   to pressure

V2= V1*T2/T1= 2*353/(20+273.15)= 2*353/293.15=2.41

Increase in volume =2.41-2 =0.41 L