The first step in the mechanism of this reaction is a rapid and reversible proto

Question

The first step in the mechanism of this reaction is a rapid and reversible protonation of the alcohol by the acid, followed in the second step by a rate-determining loss of water to form a tertiary carbocation. This process is illustrated here for 3-methyl-3-pentanol. In the third step, the carbocation loses a proton to give a mixture of alkenes. In this experiment, there are several different alkenes that can be formed. However, one of the alkenes often predominates. In Part A of this experiment, the alcohol to be dehydrated is 3-methyl-3-pentanol, while in Part B, the alcohol will be 3,3-dimethyl-2-butanol. The product compositions will be evaluated by gas chromatography. In Part C. you will dehydrate an unknown alcohol. The two possible unknown alcohols are 2-methyl-1-phenyl-2-propanol or 2-phenyl-2-butanol. Based upon the number of alkenes formed in the reaction, you will identify the structure of alcohol. You will then identify the predominant alkene through analysis of the product mixture by gas chromatography (GC) or gas chromatography-mass spectrometry (GC-MS).

Explanation / Answer

Solution :-

To find the limiting reactant we need the moles of the reactants that are used in the reaction so that using the mole ratio we can calculate the moles of tje product that can be formed from the each reactant.

The reactant which produces the lowest amount of the product is considered as the limiting reactant.

For the given equations the alcohols will be considered as limiting reactants.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.