2a. The molar solubility of a saturated solution of Bil3 is 1.32x10^-5 mol L^-1.

Question

2a. The molar solubility of a saturated solution of Bil3 is 1.32x10^-5 mol L^-1. Calculate the solubility product constant.

2b. What is the concentration of acetate ion in a saturated silver(I) acetate solution prepared with 0.0750 M AgNo3? Ksp (AgC2H3O2)= 2.0x10^-3

2c. Equal volumes of 0.0150 M barium chloride and 0.0100 M sodium sulfate are mixed. What are the concentrations of the ions present in the final solution? Ksp= (BaSO4) 1.1x10^-10?

2d.What would the final Cu+ concentration in a solution that is originally 0.10 M in both Cu+ and Pb2+, that the minimum I- concentration is present to just precipitate both Cul and Pbl2? Ksp (Cul)= 5.1x 10^-12 and Ksp= 1.4x10^-8

Explanation / Answer

2a. BiI3(s) -------> Bi3+ + 3I-

i. s 0 0

e. 0 s 3s

Ksp = s * (3s)3

Ksp = 1.32x10-5 * 9*(1.32x10-5)3

Ksp = 2.73x10-19

2b. CH3COOAg(s) ----------> CH3COO-(aq) + Ag+(aq)

i. s 0 0.0750

e. 0 s 0.0750

Ksp = 0.0750s

2x10-3 = 0.0750s

s = 2x10-3 /0.0750

s = 0.0267 M = [CH3COO-]

Questions c and d, post them in a separate question thread. I have a doubt in both of them. Hope this helps

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