Do you use K= [In] 2 [In 3+ ]/[In + ] 3 or do I have to do InCl+HCl to yield som

Question

Do you use K= [In]2[In3+]/[In+]3 or do I have to do InCl+HCl to yield some product?

8.23 x10-mol of InCl (s) is placed in 1.00 of 0.010 M HC1 (aq) at 25°C. The InCl (s) dissolves quite quickly. and then the following reaction occurs: 31n+ (aq) 2 In (s) 1n3+ (aq) As this disproportionation proceeds, the solution is analyzed at intervals to determine the concentration on In (ag) that remai Time (S 0 240 480 720 1000 1200 10000 [In'] (mol. L1) 8.23 x 10-3 6.41 x 10-3 5.00 x 10-3 3.89 x 10-3 3.03 x 10-3 3.03 x 10-3 3.03 x 10-3

Explanation / Answer

You have to use the following expression:

Ln C = LnCo - kt

Then, plot the data with this expression, (Ln[In+] vs t) and you'll get the constant k.

Using these data you'll get the following:

r2 = 0.9713

a = -4.8473

b = K = -8.824x10-4

Once you have this constant, you can actually calculate concentration of In3+. the equilibrium constant would be:

K = [In3+] / [In+]3

Hope this helps

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