121. For the reaction below, the oxidizing agent is------------------ and it----

Question

121. For the reaction below, the oxidizing agent is------------------ and it-------------------- electrons, and the reducing agent is------------------------ and it------------------------ electrons.

8 H+ + + 5 Cu+ Mn2+ + 5 Cu2+ + 4 H2O

A) ; gains 5; Cu+; loses 1

B) H+; loses 1; Cu+; gains 1

C) H+; gains 1; ; loses 5

D) Cu+; loses 1; ; gains 1

E) Cu+; loses 1; H+; gains 1

122. Which relationship is NOT correctly defined?

A) Work = E q

B) G = -n · F · E

C)

D) P = E I

E) q = n N F

123. Which of the following is NOT true for galvanic cells?

A) Galvanic cells are spontaneous.

B) Oxidation occurs at the anode and reduction occurs at the cathode.

C) Electrons move toward more negative electrical potential.

D) Galvanic cells are composed of two half-cells connected by salt bridge.

E) The salt bridge maintains electroneutrality throughout the cell.

Explanation / Answer

121) A) ; gains 5; Cu+; loses 1

Cu gets oxidized from +1 oxidation state to +2 oxidation state losing 1 e-. Therefore it is a reducing agent. The LHS of the equation des not contain the oxidizing agent which should be Mn7+. It gains 5 e-.

122) The operators(+ , - , x ) are not being displayed??

123)

Option A is correct. Galvanic cells are electrochemical cell that contain a spontaneous reaction

B is also correct

C) Electrons move from lower to higher potential. Therefore electrons move towards more positive electrical potential. Hence C) is incorrect

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