The 8-cylinder, 6.7 liter Ford diesel engine used in the F250 truck will produce

Question

The 8-cylinder, 6.7 liter Ford diesel engine used in the F250 truck will produce 800ft·lbs of torque at 1600 rpm. It also uses a turbocharger which is capable of 40 psi of boost. Boost is the additional amount of air forced into the cylinder by the turbocharger over the 1 atm the engine sucks in naturally: therefore, the cylinder has 15 psi + 40 psi = 55 psi of air in the cylinder at maximum boost pressure.

Diesel fuel is a complex mixture of compounds, but let the average chemical reaction for combustion of diesel fuel in the cylinder be approximated as follows:

C12H26 is called dodecane. C12H26 (`) + 37 2 O2 (g) 12CO2 (g) + 13H2O(`)

From the amount of air in a single cylinder 6.7L 8 calculate the heat released, Horxn, from the combustion reaction above for the two cases below, for a single cylinder.
1. No boost: cylinder pressure = 15 psi
2. Maximum boost: cylinder pressure = 55 psi
Hints:

• Let the amount of O2 in air be 21%.

• Let O2 be the limiting reagent in the reaction; this will determine how much fuel you can burn.

• Use the ideal gas equation, and let T=300 K to determine the amount of air and O2 in the cylinder.

Explanation / Answer

The 8-cylinder, 6.7 liter Ford diesel engine used in the F250 truck will produce

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