Item 19 Given the data, calculate S vap for each liquids. ( S vap= H vap/T, wher

Question

Item 19

Given the data, calculate Svap for each liquids. (Svap=Hvap/T, where T is in K)

Part A

Diethyl ether

Express your answer with the appropriate units.

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Part B

Acetone

Express your answer with the appropriate units.

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Part C

Benzene

Express your answer with the appropriate units.

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Part D

Chloroform

Express your answer with the appropriate units.

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Part E

Ethanol

Express your answer with the appropriate units.

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Part F

Water

Express your answer with the appropriate units.

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Compound Name BP(C) Hvap(kJ/mol)atBP C4H10O Diethyl ether 34.6 26.5 C3H6O Acetone 56.1 29.1 C6H6 Benzene 79.8 30.8 CHCl3 Chloroform 60.8 29.4 C2H5OH Ethanol 77.8 38.6 H2O Water 100 40.7

Explanation / Answer

At boling point of a substance, a state of equilibrium between the liquid and gas phases exitsts, G = 0.

G = H – TS

at boiling point , H – TS = 0

S =  H / T

i) Diethyl ether, given that H = 26.5 kJ/mol and T = 34.6 oC = 307.6 K

S =  H / T = (26.5 kJ/mol) / 307.6 K = 0.08615 kJ mol-1 K-1 = 0.086 * 1000 J mol-1 K-1= 86.15 J mol-1 K-1

ii) Acetone, given that H = 29.1 kJ/mol and T = 56.1 oC = 329.1 K

S =  H / T = 29.1 / 329.1 = 88.42 J mol-1 K-1

iii) Benzene, given that H = 30.8 kJ/mol and T = 79.8 oC = 352.8 K

S =  H / T = 30.8 / 352.8 = 87.30 J mol-1 K-1

iv) Chloroform, given that H = 29.4 kJ/mol and T = 60.8 oC = 333.8 K

S =  H / T = 29.4 / 333.8 = 88.07 J mol-1 K-1

v) Ethanol, given that H = 38.6 kJ/mol and T = 77.8 oC = 350.8 K

S =  H / T = 38.6 / 350.8 = 88.07 J mol-1 K-1 = 110.03 J mol-1 K-1

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