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Consider the following reduction potentials: cu^2-right arrow Cu pb^2+2e^-right

ID: 930701 • Letter: C

Question

Consider the following reduction potentials: cu^2-right arrow Cu pb^2+2e^-right arrow pb E =0.34v E =-0.13 For a galvanic cell employing the Cu, Cu^2^+ and pb^2^+ couples, calculate the maximum amount of work that would accompany the reaction of one mole of lead under standard conditions. -45.3kj -90.7kj No work can be done. The system is at equilibrium. -40.5kj A fuel cell designed to react rain alcohol with oxygen has the following net reaction: C_2H_5OH(l)+3O_2(g)+3H^2O(l) The maximum work one mole of alcohol can yield this process is 1320 kj. What is the theoretical maximum voltage this cell can achieve? 0.760 V 1.14 V 2.01 V 2.28 V Tables of standard reduction potentials are usually given at 25^0C. E^0 depends on temperature. Which of the following equations describe the temperature dependence of E^0? E^0=-delta H +T delta S E^0=nf/RT+nk E^0=delta H /nf+TdeltaS inE =delta H /RT+deltaS /R A cell is set up with copper and silver electrodes in contact with CuSO_4(aq,1.0M) and AgNO_3(aq, 26) 1.0M), respectively, at 25^0C. The standard cell potential is 4.46 V for the reaction: 2Ag^+=Cu right arrow 2A+Cu^2+ If hydrochloric acid is added to the AgNO_3 solution, forming a precipitate of Ag, the cell potential will increase can't tell what will happen remain unaffected decrease In the following nuclear equation, identify the missing product : ^43_20Ca^4^2+a right arrow +^1_1H ^44_22Ti ^44_21 Sc ^44_22Ti ^42_20 Ar

Explanation / Answer

23.

wmax= nFEcell        

        = - 2 x 96486 C x (0.34V- (-0.13V)

        = - 90 697 J = - 90.7J

The work done has by convention a minus sign.

24.

In this reaction

3O2 + 12e- = 6O2-                      n=12

2C2-    = 2C4+ + 12e-

wmax= nFEcell = 12 x 96486 C x Ecell = 1.320x106 J

Ecell = 1.14 V   

25

E = -dG/nF = -dH/nF + TdS/nF

Answer C.

26.

Ecell = Eocell – (0.0592/n) log([Cu2+]/[Ag+]2)

If ([Cu2+]/[Ag+]2 increases, then Ecell decreases.

27

alpha is 42He

For the unknown

A = 43+4 -1 = 46

Z= 20+2-1 = 21

Answer B

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