answered first two and were correct, can\'t last one (in bold). thought it was 3
ID: 931488 • Letter: A
Question
answered first two and were correct, can't last one (in bold). thought it was 3.27 but was wrong
Consider 2 cells, 1st with Al and Ag electrodes, and 2nd w/ Zn and Ni electrodes, each in appropriate 1.00 M solutions of their ions
if connected as voltaic cells in series, Ag and Ni are plated/ total potential: 2.96 V
if connected such that one cell asts as battery to power the other as an electrolytic cell, Ag and Zn are plated and 1.98 is the total potential.
If 2.7 g of metal is plated in the voltaic cell, how much metal is plated in the electrolytic cell?
Explanation / Answer
Al ===> Al3+ + 3e- E= +67V
Ag+ + e- ===> Ag E= +0.80V
Zn ===> Zn2+ + 2e- E= +0.76
Ni2+ + 2e- ===> Ni E= -0.25
((2.7g/107.868)/2)*65.38=0.823g zn
(mass/molar mass of Ag)/(2mole Ni for 1mole Ag) *molar mass of Zn
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