Question 31 An object measuring 77 milliliters will have a volume of ________ li

Question

Question 31

An object measuring 77 milliliters will have a volume of ________ liters.

0.077

77000

13

7700

770

2 points   

Question 32

Which one of the following solutions will have the greatest concentration of hydroxide ions?

1.10 M rubidium hydroxide

0.368 M calcium hydroxide

0.368 M ammonium hydroxide

0.368 M potassium hydroxide

0.368 M sulfuric acid

2 points   

Question 33

there are 30 mg of benzene in 1.0 L of this solution

100 g of the solution contains 30 g of benzene

100 g of the solution contains 30 mg of benzene

the solution is 30% by mass of benzene

the molarity of the solution is 30 M

2 points   

Question 34

There are ________ mol of bromide ions in 0.500 L of a 0.350 M solution of AlBr3.

0.150

0.0500

0.525

0.167

0.500

2 points   

Question 35

Ethanol (C2H5OH) melts at -114 °C. The enthalpy of fusion is 5.02 kJ/mol. The specific heats of solid and liquid ethanol are 0.97 J/g-K and 2.3 J/g-K, respectively. How much heat (kJ) is needed to convert 25.0 g of solid ethanol at -135 °C to liquid ethanol at -60 °C?

207.3

-13.3

6.34

3617

8.63

0.077

77000

13

7700

770

Explanation / Answer

31. 1millilitre = 0.001 L

So 77 millilitre = 77 * 0.001

= 0.077 L

32. 1.10 M rubedium hydroxide is having greatest concentration of hydroxide ions as it is a strong base.

33. 1 ppm = 1 mg / 1 L

Therefore

There are 30 mg of benzene in 1L of the solution

34. Concentration = no. Of moles / volume of solute in lt

No. Of moles of AlBr3, n = Concentration * volume of solute

n = 0.350 * 0.5

= 0.175 moles AlBr3

No. Of moles of bromide ions in AlBr3 = 0.175 mol AlBr3 *( 3 mol Br / 1 mol Al Br3)

= 0.525 moles Bromide ions.

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