D. Ag 3 PO 4 Will you please explain how to calculate the solubility. I don\'t u
ID: 933535 • Letter: D
Question
D. Ag3PO4
Will you please explain how to calculate the solubility. I don't understanding going from (3s)3 =27s4 =Ksp.. how do you get the Ksp? I have an appendix that shows them but Its not matching up on another question exactly like this one.
from the Ksp then you need to figure out what s is = thus (Ksp/27s)1/4 = s...
So I need to understand out to get the Ksp from (3s)3 =27s4 =Ksp
1. chromium(III) hydroxide is MORE soluble than 2. chromium(III) hydroxide is LESS soluble than A. Mg(OH)2 B. Fe(OH)3 C. Ag2SO3D. Ag3PO4
Will you please explain how to calculate the solubility. I don't understanding going from (3s)3 =27s4 =Ksp.. how do you get the Ksp? I have an appendix that shows them but Its not matching up on another question exactly like this one.
from the Ksp then you need to figure out what s is = thus (Ksp/27s)1/4 = s...
So I need to understand out to get the Ksp from (3s)3 =27s4 =Ksp
Explanation / Answer
To calculate solubity write the equation for solubility.
For Mg(OH)2
Mg(OH)2 ---> Mg2+ + 2OH-
s 2s
Ksp = [Mg2+][OH-]2
= s (2s)2
= s * 4s2
=4s3
For Fe(OH)3
Fe(OH)3 ---> Fe2+ + 3OH-
s 3s
Ksp = [Fe2+][OH-]2
= s (3s)3
= s * 27s3
=27s4
For Ag2SO3
Ag2SO3 ---> 2Ag2+ + SO32-
2s s
Ksp = [Ag+]2[SO32-]
= (2s)2 *s
= 4s2 *s
=4s3
For Ag3PO4
Ag3PO4---> 3Ag2+ + PO43-
3s s
Ksp = [Ag+]3 [PO43-]
= (3s)3 *s
= 27s3 *s
=27s4
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