t The Arrhenius Equation: Graphical Method There al factors that affect the rate

Question

t The Arrhenius Equation: Graphical Method There al factors that affect the rate of a reaction. These fact nclude temperature, activation energy, steric factors (orientation, and also collision frequency, which changes with concentration and phase All the factors that affect reaction rate can be summarized an equation called the ius equation where h is the rate constant, A is the frequency factor, Ea is he activation energy R 8.314 J (mol K the universal gas constant. and T isthe absolute temperat Figure In A rtain reaction has an activation energy of 01.okJ/moland a frequency factor of A 3.70 o12. .what is the rate constant, k, of this reaction at 20.0 C Express your answer th the appropriate units. Indicate the multiplication of its expl tly either with a multiplication dot lasteris or a dash. OHDA Value Units Hints My Answers Give Up Review Part The linear form of the Arrhenius equation The Amheni be rearranged to a form that the eq tion for a straight Ink where yisln R. m is the slope or zis nd bis the y-int A The linearity of this eq is ustrated graphically in the image.Eiasare 10 Part B An unknown reaction was observed. and the following data were collected 352 108 420 185 Determine the activation energy for this reaction. Express your answer with the appropriate units. Value Units

Explanation / Answer

Part A)

They ask us for the K value

this is given as follows:

K = A*exp(-E/RT)

K = 3.7*10^12*exp[-61/(8.31)*(26+273)] = 3.7*10^12 * 0.975 = 3.61*10^12

K = 3.61*10^12 same units as A

K = 3.61*10^12 M-1s-1

Part B)

LEt us have 2 equations

ln K1 = -(E/R)*(1/T1) + lnA (1)

ln K2 = -(E/R)*(1/T2) + lnA (2)

Assume A1= A2 and E1=E2 since it is the same reaction, besides R is constant anywhere

Then Substract 1 and 2

ln K1- ln K2 = -(E/R)*(1/T1) +(E/R)(1/T2)

ln(K1/K2) = -(E/R)(1/T1 - 1/T2)

Where

K1 = 109

T1= 352

K2 = 185

T2 = 426

E = ?

R = 8.313 kJ/kmol

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